6/(y^2+2y)-(y+1/y+2)=2/y

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Solution for 6/(y^2+2y)-(y+1/y+2)=2/y equation:


D( y )

y = 0

y^2+2*y = 0

y = 0

y = 0

y^2+2*y = 0

y^2+2*y = 0

y^2+2*y = 0

DELTA = 2^2-(0*1*4)

DELTA = 4

DELTA > 0

y = (4^(1/2)-2)/(1*2) or y = (-4^(1/2)-2)/(1*2)

y = 0 or y = -2

y in (-oo:-2) U (-2:0) U (0:+oo)

6/(y^2+2*y)-y-(1/y)-2 = 2/y // - 2/y

6/(y^2+2*y)-y-(1/y)-(2/y)-2 = 0

6/(y^2+2*y)-y-y^-1-2*y^-1-2 = 0

6/(y^2+2*y)-y-1/y-2/y-2 = 0

y^2+2*y = 0

y^2+2*y = 0

y*(y+2) = 0

y+2 = 0 // - 2

y = -2

y*(y+2) = 0

6/(y*(y+2))-y-1/y-2/y-2 = 0

6/(y*(y+2))+(-y*y*(y+2))/(y*(y+2))+(-1*(y+2))/(y*(y+2))+(-2*(y+2))/(y*(y+2))+(-2*y*(y+2))/(y*(y+2)) = 0

6-y*y*(y+2)-1*(y+2)-2*(y+2)-2*y*(y+2) = 0

6-y^3-2*y^2-2*y^2-y-2*y-4*y-4-2 = 0

4-y^3-2*y^2-2*y^2-y-2*y-4*y-4 = 0

-y^3-2*y^2-2*y^2-3*y-4*y = 0

-y^3-4*y^2-7*y = 0

-y^3-4*y^2-7*y = 0

-y*(y^2+4*y+7) = 0

y^2+4*y+7 = 0

DELTA = 4^2-(1*4*7)

DELTA = -12

DELTA < 0

-y = 0

-y/(y*(y+2)) = 0

-y/(y*(y+2)) = 0 // * y*(y+2)

-y = 0

-1*y = 0 // : -1

y = 0

y in { 0}

y belongs to the empty set

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